Question

Find the probablity that you get a total of more than
3 in a throw of 2 dice.

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{ Find the probablity that you get a total of more than }\hspace{.33em}\\~\\
& \normalsize \text{ 3 in a throw of 2 dice .}\hspace{.33em}\\~\\
\end{align}}\)

Answer 2

more than 3 ->
6x4
(1,2,3,4,5,6) and (3,4,5,6)

all the possibilites ->
6x6
(1,2,3,4,5,6) and (1,2,3,4,5,6)

Answer 3

is it 24/36=2/3

Answer 4

you could just do
\[\Pr(T>3)=1-\Pr(T \le3)\]

Answer 5

would be less ways that way

Answer 6

and you know there are 36 combinations in total for rolling any number.

Answer 7

yes chris is correct..

btw i forgot about (3,1), (4,1),... (3,2), (4,2),... combinations I think its better to follow chris 's way

Answer 8

1,1
2,1 2,1 are the only combinations less than or equal to 3

Answer 9

is it 11/12

Answer 10

\[\Pr(X \le3)=\frac{ 1 }{ 36 }+\frac{ 2 }{ 36 }\]

Answer 11

ye

Answer 12

looks good

Answer 13

11/12 is correct

Answer 14

awesome