Question

Hi can you please help me to solve this prob?
Find the number divisors of 240

Answer 1

the first divisor is 2:
240/2=120
120/2=60
60/2=30
30/2=15
15/3=5
5/5=1

each time you divide new number by the it's smallest divisor:

thus your divisors are 2, 4, 8, 16, 6, 10, 48, 30, 15, 60, 5, 120, 240, 1, 3, 80 , 24, 12, 20, 40, that's all if i didn't forgot anything
prime factorization is 2*2*2*2*3*5

Answer 2

to find divisors of 240, first write it's prime factorization, then calculate all of the combinations between the prime factors

Answer 3

@JMark

Answer 4

what kind of divisors?
2.4 is also a divisor :)

Answer 5

is the answer 20

Answer 6

\(240 = 2^4*3*5\)

So, any divisor of \(240\) will be of form \(2^a*3^b*5^c\),
where \(0\le a\le 4\) and \(~0\le b,c\le 1\)

Answer 7

yeah gane is right

Answer 8

mom=Mars Orbiter Mission

Answer 9

mom=mother of mankind (;

Answer 10

Notice that we can choose the exponent \(a\) in \(5\) ways,
\(b\) in \(2\) ways,
\(c\) in \(2\) ways

therefore total number of positive divisors = \(5*2*2=20\)

Answer 11

i learnt this stuff 1 year ago here now i forgot it

Answer 12

same

Answer 13

looks like Mister.Mark is not in a hurry to see our explanations @JMark

Answer 14

i just remembered the pattern (a+1)(b+1)(c+1)....=no of divisors

Answer 15

looks like he did it himself (;