Question

Derivative of y= (1+x^1/2)^2

Answer 1

here you have to apply the formula of the derivative of a function of function, namely:
\[\frac{{df}}{{dx}} = 2\left( {1 + {x^2}} \right) \cdot \frac{{d\left( {1 + {x^2}} \right)}}{{dx}}\]

Answer 2

chain rule right? take the exponent bring it the front then leave that and then proceed to take the derivative of whatever is inside of the parenthesis

Answer 3

correct!

Answer 4

oops.. I made an error, here is the right step:
\[\frac{{dy}}{{dx}} = 2\left( {1 + \sqrt x } \right) \cdot \frac{{d\left( {1 + \sqrt x } \right)}}{{dx}}\]

Answer 5

Thank you! I understand it now