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Mathematics 15 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

if L is the length and W is the width, then we can write: \(L=5\cdot W\)

OpenStudy (michele_laino):

hint: the perimeter of your rectangle is: \(2(L+W)=96\)

OpenStudy (michele_laino):

now I substitute, so I get this: \(2(5W+W)=96\) please solve that equation for \(W\)

OpenStudy (anonymous):

how?

OpenStudy (lynfran):

start with the bracket ...add like terms ...(5W+W)

OpenStudy (anonymous):

would that equal 5w?

OpenStudy (lynfran):

no

OpenStudy (anonymous):

?

OpenStudy (lynfran):

ok eg... what W+W=?

OpenStudy (anonymous):

W

OpenStudy (lynfran):

no 2W

OpenStudy (michele_laino):

what is: \(5W+W=...\)

OpenStudy (michele_laino):

you have to sum: \(5+1\)

OpenStudy (anonymous):

6

OpenStudy (michele_laino):

ok! so we can write: \(5W+W=6W\)

OpenStudy (michele_laino):

now what is \(2\cdot 6W=...?\)

OpenStudy (anonymous):

12w?

OpenStudy (michele_laino):

correct!

OpenStudy (michele_laino):

so we get this equation: \(12W=96\)

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

If I divide both sides by 12, I get: \[\frac{{12W}}{{12}} = \frac{{96}}{{12}}\]

OpenStudy (michele_laino):

so, what is \(96/12=...?\)

OpenStudy (michele_laino):

|dw:1444586909931:dw|

OpenStudy (anonymous):

so solve 96 divided by 12 right?

OpenStudy (michele_laino):

right!

OpenStudy (anonymous):

8!

OpenStudy (michele_laino):

correct! you got the right answer

OpenStudy (anonymous):

Great thank you

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