Question

The number of bacteria initially in a culture is 4,518 . If the number increases at the continuous hourly rate of 5.32 %, how many bacteria will be present at the end of 13 hours? Count only whole bacteria.

Answer 1

\[y(t)=ae ^{kt}\] a is your init value, k is your % of growth, and t is your time in hours so
\[y = 4518e ^{0.0532*13}\]

Answer 2

9,022.030 or 9022 as a whole number?

Answer 3

ya 9022

Answer 4

Ok thanks for explaining the formula to me :)

Answer 5

Np. :)