A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution.

Ka HC2H3O2 = 1.80E-5

Question

A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution.

Ka HC2H3O2 = 1.80E-5

lena772 · Answer

@Cuanchi I've tried the same method with this and got it wrong twice.

cuanchi · Answer

this is sodium acetate it is a salt and the HCl acid you may have a buffer here. Acetic/Acetate

lena772 · Answer

does that mean i can use hasselbach?

photon336 · Answer

What was the method you used before?

cuanchi · Answer

you do the titration of the Acetate with the HCl and calculate how much acetate and Acetic you have. Yes you can use Hasselbach

lena772 · Answer

4.7447274949+log(1.2/0.8)
=4.92 

Is this right?

lena772 · Answer

I used the hasselbach method but i may have plugged in something wrong

cuanchi · Answer

let me think doesnt looks that  easy how i was thinking in the biguining

lena772 · Answer

I submitted and that was right. I must have been plugging stuff in wrong. Thanks for all your help :)

cuanchi · Answer

ok you are lucky!!