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Find the volume of the solid that results when the region bounded by y=0, x=0, x=1, and y=x^2+1 is revolved around the y-axis using discs/washers.
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"...using discs/washers" it's way easier just using calculus have you had a go?
I know how to use disks/washers for most problems, but after I graphed this one, I couldn't figure it the equation. It's wrong, but I did this : \[\pi \int\limits_{0}^{2}(\sqrt{y-1}^2-(0)^2dy\]
Hmm :) Ya if we look at the graph...
|dw:1444636132588:dw|Notice that down here, your left boundary is NOT the function x!
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