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Mathematics 14 Online
OpenStudy (loser66):

I don't get what my Prof did in class. Some one explains me, please.

OpenStudy (loser66):

OpenStudy (anonymous):

\[e^{2\pi i}=1\] right?

OpenStudy (loser66):

Problem is not there, that argument is ok, but why it is applied to the equation from the right when \(z_1z_2 \) is arbitrary?

OpenStudy (anonymous):

since \(e^{2\pi i}=1\) then \[\log(z_1z_2)=\log(z_1z_2e^{2\pi i})\]

OpenStudy (anonymous):

thence \[\log(z_1)+\log(z_2)+\log(e^{2\pi i})\]

OpenStudy (loser66):

I have \(2i n \pi\) , not just \( 2\pi i\).

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