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Mathematics 27 Online
OpenStudy (anonymous):

Automobile airbags inflate following a collision. The impact triggers the following chemical reaction (shock sensitive reaction), during which a large volume of gas is produced to fill the airbag. 2NaN3(s) --> 2Na(s) 3N2 (g) d) Given the following enthalpies of formation, determine the standard enthalpy change for the reaction (deltaH) per mol of NaN3 reacted Substance Delta H NaN3(s) 21.7 kJ/mol N2 (s) 0 kJ/mol Na (g) 0 kJ/mol What is the change in internal energy for the reaction when 1.0 mol of NaN3 is consumed? Calculate w, q, and delta E if 2.0 mold of NaN3 were

OpenStudy (anonymous):

I meant "delta U if 2.0 mol of NaN3 were consumed in a given experiment?

OpenStudy (anonymous):

@thomaster please help

OpenStudy (anonymous):

enthaply change = enthalpy of products - enthalpy of reactants

OpenStudy (anonymous):

this should probs be in chemistry lel

OpenStudy (anonymous):

okay, sorry about that. I forgot to switch the topic thingy.

OpenStudy (anonymous):

okay did that and I got -43.4kJ/mol rxn

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

now for: What is the change in internal energy for the reaction when 1.0 mol of NaN3 is consumed? We use our answer for the first bit. we found that 2NaN3(s) --> 2Na(s) 3N2 (g) has \[\Delta H\]=043.4 kj/mol

OpenStudy (anonymous):

-43.4* so using molar ratio, 2moles of NaN3 gives us, -43.4 kj/mol. hence 1 mol will give-21.7 kj/mol

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