Question

18y^5-8y^4/2y^2 simplify as much as possible

Answer 1

i got 9y^3+4y^2

Answer 2

@Data_LG2

Answer 3

@Michele_Laino

Answer 4

we can simplify the second term, using the rules of division of powers with the same basis:
\[\frac{{8{y^4}}}{{2{y^2}}} = \frac{8}{2} \cdot {y^{4 - 2}} = ...?\]
please simplify

Answer 5

sorry is your expression like this:
\[\frac{{18{y^5} - 8{y^4}}}{{2{y^2}}} = ...?\]

Answer 6

so the first term is correct! \(9y^3\)

Answer 7

yes

Answer 8

the second term is:
\[\frac{{ - 8{y^4}}}{{2{y^2}}} = \frac{{ - 8}}{2} \cdot {y^{4 - 2}} = ...?\]

Answer 9

-4y^2

Answer 10

right so your second term is:
\(-4y^2\), and the complete result is:
\(9y^3-4y^2\)

Answer 11

thank you. can you check one more

Answer 12

ok!

Answer 13

x^2+10x+26/x+6 i have to get the quotient and the remainder. I got x+4 & 2 for the remainder

Answer 14

your answer is correct, since we have:
\[\left[ {\left( {x + 6} \right) \cdot \left( {x + 4} \right)} \right] + 2 = {x^2} + 10x + 26\]

Answer 15

thank you. sorry but can you check another one?

Answer 16

more explanation:
it is a proof, since we have:
(quotient times divisor) plus remainder = dividend

Answer 17

ok!

Answer 18

3v^2(v+8)-7(v+8) rewrite by factoring out (v+8) I got (v+8)(3v^2-7)

Answer 19

correct!

Answer 20

thanks