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Mathematics 14 Online
OpenStudy (carolinar7):

Help Medal!

OpenStudy (carolinar7):

\[y=\frac{ 2+5x }{ 3x }\]

OpenStudy (carolinar7):

How do you find the Range

OpenStudy (carolinar7):

@Nnesha

OpenStudy (carolinar7):

@phi

OpenStudy (carolinar7):

@ybarrap

OpenStudy (carolinar7):

@pooja195

OpenStudy (ybarrap):

First find those point where the function does not have a value. Look at the denominator. What value can x NOT be?

OpenStudy (carolinar7):

0

OpenStudy (ybarrap):

Correct! So all other values are allowed. Right?

OpenStudy (carolinar7):

Then I got {yly cannot = -2/5}

OpenStudy (carolinar7):

But My book says {yly cannot = 5/3}

OpenStudy (carolinar7):

D: {x l x cannot = 0}

OpenStudy (ybarrap):

Similarly, for the range $$ y=\frac{ 2+5x }{ 3x }\\ \implies x = \frac{2}{3 y-5} \text{ and } 3y\ne5\\ \implies y\ne \frac{3}{5} $$ All other values of y are allowed. So what is the range?

OpenStudy (ybarrap):

Correction: $$ y\ne \cfrac{5}{3} $$

OpenStudy (carolinar7):

Why did you do the inverse though

OpenStudy (ybarrap):

We solved for x because we wanted to find the valid values of y and this will help us find it: $$ y=\frac{ 2+5x }{ 3x }\\ 3xy=2+5x\\ 3xy-5x =2\\ x(3y-5)=2\\ x=\cfrac{2}{3y-5} $$ This shows us that y can not be equal to 5/3 but all other values are ok.

OpenStudy (ybarrap):

If y = 5/3 then x will "blow up" and that's not good

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