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OpenStudy (carolinar7):
\[y=\frac{ 2+5x }{ 3x }\]
OpenStudy (carolinar7):
How do you find the Range
OpenStudy (carolinar7):
@Nnesha
OpenStudy (carolinar7):
@phi
OpenStudy (carolinar7):
@ybarrap
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OpenStudy (carolinar7):
@pooja195
OpenStudy (ybarrap):
First find those point where the function does not have a value. Look at the denominator. What value can x NOT be?
OpenStudy (carolinar7):
0
OpenStudy (ybarrap):
Correct! So all other values are allowed. Right?
OpenStudy (carolinar7):
Then I got {yly cannot = -2/5}
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OpenStudy (carolinar7):
But My book says {yly cannot = 5/3}
OpenStudy (carolinar7):
D: {x l x cannot = 0}
OpenStudy (ybarrap):
Similarly, for the range
$$
y=\frac{ 2+5x }{ 3x }\\
\implies x = \frac{2}{3 y-5} \text{ and } 3y\ne5\\
\implies y\ne \frac{3}{5}
$$
All other values of y are allowed.
So what is the range?
OpenStudy (ybarrap):
Correction:
$$
y\ne \cfrac{5}{3}
$$
OpenStudy (carolinar7):
Why did you do the inverse though
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OpenStudy (ybarrap):
We solved for x because we wanted to find the valid values of y and this will help us find it:
$$
y=\frac{ 2+5x }{ 3x }\\
3xy=2+5x\\
3xy-5x =2\\
x(3y-5)=2\\
x=\cfrac{2}{3y-5}
$$
This shows us that y can not be equal to 5/3 but all other values are ok.
OpenStudy (ybarrap):
If y = 5/3 then x will "blow up" and that's not good