Question

Leslie rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 11?

2 over 36
3 over 36
4 over 36
5 over 36

Answer 1

@Mehek14 @Directrix

Answer 2

From the sample space, I see two way to get a sum of 11:

(5,6) and (6,5).

Answer 3

Probability is the number of desired outcomes divided by the number of possible outcomes.

P(sum of 11) = ?/? @geny55 Any idea?

Answer 4

By desired outcome, I mean the number of ways to get what it is you want when you throw the number cubes - in this case, a sum of 11.

Possible outcomes is the number of elements in the sample space.

Answer 5

idk

Answer 6

How many ways to get sum of 11?

>From the sample space, I see two way to get a sum of 11: (5,6) and (6,5).

Answer 7

d?

Answer 8

How many ways to get sum of 11?

There are two ways to get a sum of 11. So, the number of desired outcomes is 2.

There are 36 possible outcomes.

The probability = 2/36 which is NOT option D.

Answer 9

A?

Answer 10

@Directrix

Answer 11

2 over 36 is correct.

Answer 12

Sarah used a probability simulator to roll a 12-sided number cube 100 times. Her results are shown in the table below:


Number on
the Cube Number of
Times Rolled
1
18
2
5
3
10
4
12
5
16
6
5
7
8
8
14
9
2
10
5
11
2
12
3


Using Sarah's simulation, what is the frequency of rolling a 2 on the number cube?
100 over 5
100 over 95
95 over 100
5 over 100

Answer 13

@Directrix

Answer 14

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