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How do you find exact value? Cos (- 3pi/4)
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hint: we can write this: \[\begin{gathered} \cos \left( { - \frac{{3\pi }}{4}} \right) = \cos \left( {\frac{\pi }{4} - \pi } \right) = \hfill \\ \hfill \\ = \cos \left( {\frac{\pi }{4}} \right)\cos \left( \pi \right) + \sin \left( {\frac{\pi }{4}} \right)\sin \left( \pi \right) = ...? \hfill \\ \end{gathered} \]
What happened to the three?
we have: \[\frac{\pi }{4} - \pi = - \frac{{3\pi }}{4}\]
cos (-theta) = cos theta
cos(-3pi/4)= cos (3pi/4)
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How does that end up as - 1/√ 2?
cos(3*180/4)= cos(3*45) = cos135
cos(90+45) = -sin45
=-1/square root of 2
Wow. That was way simpler than I made it out to be. Thanks a bunch!
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