Use the figure below to estimate the indicated derivatives, or state that they do not exist. If a derivative does not exist, enter dne in the answer blank. The graph of f(x) is black and has a sharp corner at x=2. The graph of g(x) is blue.
Well, try using the product rule on this: h(x)=f(x)g(x) to find h'(x)
I am not sure how to do that from the given graph
Don't worry about the graph, just use the product rule on the algebra, I know it's kind of strange so I'll show you: h(x)=f(x)g(x) now to differentiate we just do the same thing to both sides: h'(x) = [f(x)g(x)]' Now we can evaluate this a little further by using the product rule: [f(x)g(x)]'=f'(x)g(x)+f(x)g'(x) So now you have a full equation for h'(x) in terms of stuff you can find! h'(x) = f'(x)g(x)+f(x)g'(x)
okay, i know that, but what do i use as my F(x) and g(x)?
You obtain those directly off of the graph there, so for instance f(1)=1.5 and you can tell because f is a straight line with a -1/2 slope if you look at it it directly hits integer points on either side.
okay well the only one i am having trouble with is h'(3)
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