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Mathematics 16 Online
OpenStudy (anonymous):

Math help please!

OpenStudy (freckles):

\[\frac{b-a}{n}=\frac{3}{n}\] just choose b and a such that this equation holds where b>a

OpenStudy (freckles):

once you do that we will move on to the rest

OpenStudy (anonymous):

b=5 and a=2

OpenStudy (freckles):

sounds good you could also have chosen b=3 and a=0 but that works too (you can choose a whole of bunch of things obviously :p)

OpenStudy (anonymous):

Oh I hadn't thought of those

OpenStudy (freckles):

\[\int\limits_2^5 f(x) dx \text{ is what we have so far } \\ \text{ so we need } f(a+i \cdot \Delta x)=1+i \cdot \frac{3}{n} \] so now we need to choose a function f such that this true let me rewrite just a little: a is 2 you chose this and Delta x = (5-2)/n or 3/n so you have \[f(2+i \frac{3}{n})=1+i \frac{3}{n}\]

OpenStudy (freckles):

so we need to choose a function f such that this is true

OpenStudy (freckles):

like say we have f(x)=x-1 what would this give you if you replace x with 2+i*3/n

OpenStudy (anonymous):

x?

OpenStudy (freckles):

we want to choose f such that: \[f(2+i \frac{3}{n})=1+i \frac{3}{n} \\ \text{ I suggested } f(x)=x-1 \\ \text{ since if we replace } x \text{ with } 2+i \frac{3}{n} \\ \text{ we do get } \\ f(2+i \frac{3}{n})=2+i \frac{3}{n}-1 \text{ which is equal to } 1+i \frac{3}{n}\]

OpenStudy (freckles):

which is what we wanted

OpenStudy (freckles):

\[\int\limits_2^5 (x-1) dx\] is one possibility on how we could choose the integral

OpenStudy (anonymous):

So then I integrate it?

OpenStudy (freckles):

it just says write the integral

OpenStudy (anonymous):

Oh thats not one of the choices :(

OpenStudy (freckles):

well you choose the upper and lower limit to be 5 and 2 respectively

OpenStudy (freckles):

if there are choices then that is a hint on how to choose the limit to get the integral they want

OpenStudy (freckles):

so what are the limit choices in the multiple choice?

OpenStudy (freckles):

so you do know 4-1=3 right? of course you do so we could have chosen b to be 4 and a to be 1

OpenStudy (freckles):

see if you can find the proper function by using our example above when we chose our limits to be 2 and 5

OpenStudy (anonymous):

Haha okay

OpenStudy (anonymous):

Im thinking its B where the limits are 1 to 4 of x

OpenStudy (freckles):

so this means you think \[f(1+i \frac{3}{n})=1+i \frac{3}{n} \text{ means } f(x)=x\] ?

OpenStudy (freckles):

don't be afraid to say yes :)

OpenStudy (anonymous):

Yes I think so

OpenStudy (freckles):

that is true

OpenStudy (freckles):

and your answer is right if you do replace the x's in f(x)=x with 1+i*3/n you do get f(1+i3/n)=1+i3/n great job

OpenStudy (freckles):

do you have any questions

OpenStudy (anonymous):

No thank you so much!! You were very helpful!!

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