Question

What is the equation of the quadratic graph with a focus of (3, −1) and a directrix of y = 1?

f(x) = −one fourth (x − 3)2 + 1
f(x) = −one fourth (x − 3)2
f(x) = one fourth (x − 3)2 + 1
f(x) = one fourth (x − 3)2

If I get this answer right then I could probably do the rest :)

Answer 1

what have you got so far?
its been a while since i did these and i only recall them dimly

Answer 2

you take any point (x,y) and find expressions for the distance between this point and the focus of the parabola. Then find perpendicular distance between the point and the directrix

These 2 distances are equal

Answer 3

I know I have to find the focal length (inbetween the coordinates) and then substitute it for 1/4p = a

Answer 4

yes this is another way to do it which i cant remember either

Answer 5

ok lemme take a minute to figure it out.