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Mathematics 15 Online
OpenStudy (anonymous):

http://prntscr.com/8rmvz6 http://prntscr.com/8rmw9h http://prntscr.com/8rmx96

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

@Haseeb96

OpenStudy (dan815):

you did the first one right

OpenStudy (dayakar):

2) d

OpenStudy (dayakar):

f(x)=4x+3,g(x)=x+2

OpenStudy (anonymous):

any ideas on the last one

OpenStudy (dayakar):

3)(4,2)

OpenStudy (dan815):

y=f(x) for an inverse function you want to see the x value for your y value x=f^-1(y) y=f^-1(x) but this is the same thing as y=f(x) taking this graph and rotating the graph around so that y is the domain and x is the range or you can also think about this as the reflection across the y=x line as you're just flipping the places of x and y

OpenStudy (dan815):

you see the point (2,4) on your graph so (4.2) should be on the inverse graph, if you flip the y and x around

OpenStudy (dan815):

http://prntscr.com/8s7452

OpenStudy (dayakar):

(2,4) is one point on given graph inverse of it is (4,2), am i right

OpenStudy (dan815):

ya if you get 4 for inputting 2 the inverse is supposed to tell you what u input if ur ouput was 4

OpenStudy (anonymous):

so the answer would be 4,2?

OpenStudy (dan815):

2-->4 input was 2 output was 4 the inverse graph tells you what the input was for a given output 4-->2 output is the new input into this inverse function and u shud get 2 back

OpenStudy (dan815):

make sense?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ty

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