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OpenStudy (anonymous):
@Directrix
OpenStudy (anonymous):
@Haseeb96
OpenStudy (dan815):
you did the first one right
OpenStudy (dayakar):
2) d
OpenStudy (dayakar):
f(x)=4x+3,g(x)=x+2
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OpenStudy (anonymous):
any ideas on the last one
OpenStudy (dayakar):
3)(4,2)
OpenStudy (dan815):
y=f(x)
for an inverse function
you want to see the x value for your y value
x=f^-1(y)
y=f^-1(x)
but this is the same thing as
y=f(x) taking this graph and rotating the graph around so that y is the domain and x is the range
or you can also think about this as the reflection across the y=x line as you're just flipping the places of x and y
OpenStudy (dan815):
you see the point (2,4) on your graph so (4.2) should be on the inverse graph, if you flip the y and x around
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OpenStudy (dayakar):
(2,4) is one point on given graph
inverse of it is (4,2), am i right
OpenStudy (dan815):
ya if you get 4 for inputting 2
the inverse is supposed to tell you what u input if ur ouput was 4
OpenStudy (anonymous):
so the answer would be 4,2?
OpenStudy (dan815):
2-->4 input was 2 output was 4
the inverse graph tells you what the input was for a given output
4-->2 output is the new input into this inverse function and u shud get 2 back
OpenStudy (dan815):
make sense?
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