Question

locate the foci of the ellipse

Answer 1

first of all )
is it horizontal or vertical ?

Answer 2

a > b
if a is under the x variable then it's horizontal
and if it's under the y variable then it would be vertical :=))

Answer 3

horizontal

Answer 4

right
foci for horizontal ellipse \[\huge\rm (h \pm c ,k)\] where (h,k) is the center
to find value of use the equation \[\huge\rm c^2 = a^2-b^2\] plugin a and b value solve for c
and then add/subtract c value into x-coordinate of the center

Answer 5

can u help me nnesha when ready i just need checking

Answer 6

alright
let me know if you have any question osama :=))

Answer 7

\[c=\sqrt{1175}\]

Answer 8

c = 34.3

Answer 9

hmm did you take square of a
36^2 ???

Answer 10

its already squared at the denominator \[\frac{ (x-h)^2}{ a^2 }+\frac{{(y-k)^2}}{b^2}=1\]
standard form equation

Answer 11

a^2 = 36
b2 =11

Answer 12

b^2 **

Answer 13

i'm confused now, i thought i had to plug in
c^2=a^2-b^2
c^2=36^2-11^2
c^2=1296-121

Answer 14

i take it that's wrong then

Answer 15

look at the general form equation of a circle
a and b already squared
a =6
a^2 = 36