Question

given that one zero is -4 find all zeros of p(x)=x^3+x^2-22x-40

Answer 1

i got 5,-4, and -2

Answer 2

yes, correct

Answer 3

thank you :3

Answer 4

All I did is checked via wolfram, not much, but you are welcome in any case :)

Answer 5

Here's a way to check

If you claim that `-4 is a zero` then plugging in x = -4 should make p(x) = 0

Let's check

p(x)=x^3+x^2-22x-40
p(-4)=(-4)^3+(-4)^2-22(-4)-40 ... replace every x with -4
p(-4)=-64+16+88-40
p(-4)=0

since the result is 0, the claim `-4 is a zero` is true

You would test the other roots the same way