Find an equation of the line. PLEASE HELP

Question

unicornpoopcookies · Answer

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shadowlegendx · Answer

Do you have an idea of how to solve this?

unicornpoopcookies · Answer

not at all I keep getting it wrong its driving me insane!!!!!

shadowlegendx · Answer

Through (-3, -9); parallel to 2x + 3y= 5

unicornpoopcookies · Answer

So I know I must make it in mx plus b form

unicornpoopcookies · Answer

so I subtract -2x from both sides

shadowlegendx · Answer

First thing we have to do is get 2x + 3y = 5 into slope intercept form.

2x + 3y = 5

We basically have to get y = something

2x + 3y = 5

Subtract 2x from both sides

3y = -2x + 5

Divide both sides by 3

y = -2x/3 + 5/3

Now, we know that this line passes through points (-3, -9) with -3 being the x and -9 being the y.

It also tells us that this line is parallel to 2x + 3y = 5. We solved for it, and we now have the slope which is -2/3.

Now we use point slope form. That is...

$$y - y _{1} = m(x - x _{1})$$

shadowlegendx · Answer

Parallel means that both lines have the same slope btw.

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They rise and fall at the same slope, thus they are parallel.

unicornpoopcookies · Answer

Yeah I know if i get the slope of one i found the same as the other.

unicornpoopcookies · Answer

I get the y equalls mx plus 6 right just not the other step

unicornpoopcookies · Answer

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