Question

use the given values to find an equation of the form f(x) ax^2+bx+c
f(1)=4, f(2)=12, f(4)=46

I have a math test tomorrow, so some help on this would be great!

Answer 1

I will do the first one
f(x)=ax^2+bx+c
f(1)=4 means f(x)=4 and the x value is 1.
So, replace f(x) with 4 and change the x values to 1
f(1)=4=a(1)^2+b(1)+c
4=a+b+c

Answer 2

you need to substitute the numbers for the x's

Answer 3

it should be possible............

Answer 4

Ah ok , zale's got this ^_^ he'll clarify. (he said the prev answer is wrong zale.)
i think you forgot to say ^2
so it's 4=(1)a^2+b(1)+c(1)

Answer 5

oh no.. hmm, zale should be right... it's a(1)^2 so it's 4=a+b+c...

Answer 6

the answer should be a trinomial......

Answer 7

hmm @Zale101

Answer 8

my teacher says these are monster problems........

Answer 9

Lapshaman, i did the first equation for you. In the beginning, i made it clear that i left the rest for you to continue.

Answer 10

So please, participate and engage in your question so you can make your learning process easier to grasp

Answer 11

I don't think you are doing it right tho, all three need to be compared at the same time, something like:

a+b+c=4
4a+2b+c=12
16a+4b+c=46

Answer 12

Correct. You can either use the elimination or the substitution method.

Answer 13

how?

Answer 14

Using the elimination method
equation 1: a+b+c=4
equation 2: 4a+2b+c=12
equation 3: 16a+4b+c=46

subtract eq 1 and 2 together and subtract 1 and 3 together
After doing that', you add both equation together (#1-#2)+(#1-#3)

Answer 15

oh, I get it!!

Answer 16

that gives me a bunch of negatives.....