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x, x + 4, and 20. If the length of the longest side is 20, which value of x would make the triangle acute?
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see for a triangle, the sum of any two sides must be greater than the third side.. so x+(x+4)>20 gives 2x>16 gives x>8
now we have to find the condition for which the triangle will be acute
for the triangle to be acute a^2+b^2>c^2 where a,b, c are the length of the sides and c is the longest side
here a=x,b=x+4 and c=20 so you need to solve for x when x^2+(x+4)^2>20^2
this gives on simplification (x+16)(x-12)>0
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hence x>12
again x+4<20 this gives x<16 so we have an inequality 12<x<16
@jmitch98
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