Question

At t = 0, a particle is located at x = 25 m and has a velocity of 15 mis in the positive x direction. The
acceleration of the particle varies with time as shown in the diagram. What is the velocity of the
particle at t = 5.0 s?

Answer 1

we can solve your problem with vector calculus. Position and velocity at time \(t=0\) can be written as below:
\[\vec r\left( 0 \right) = \left( {x\left( 0 \right),y\left( 0 \right)} \right) = \left( {25,0} \right)\]
\[\vec v\left( 0 \right) = \left( {15,0} \right)\]

Answer 2

but it is written in the answers +30 m/s