@trwatkins1 @YoungStudier @adovbush
i have another questions after this one :)
b
are you sure?
You want to find the equation for a line that passes through the two points: (-3,4) and (2,-1). First of all, remember what the equation of a line is: y = mx+b Where: m is the slope, and b is the y-intercept First, let's find what m is, the slope of the line... The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal. For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form: So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-3,4), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-3 and y1=4. Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=2 and y2=-1. Now, just plug the numbers into the formula for m above, like this: m= -1 - 4 2 - -3 or... m= -5 5 or... m=-1 So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this: y=-1x+b Now, what about b, the y-intercept? To find b, think about what your (x,y) points mean: (-3,4). When x of the line is -3, y of the line must be 4. (2,-1). When x of the line is 2, y of the line must be -1. Because you said the line passes through each one of these two points, right? Now, look at our line's equation so far: y=-1x+b. b is what we want, the -1 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,4) and (2,-1). So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!. You can use either (x,y) point you want..the answer will be the same: (-3,4). y=mx+b or 4=-1 × -3+b, or solving for b: b=4-(-1)(-3). b=1. (2,-1). y=mx+b or -1=-1 × 2+b, or solving for b: b=-1-(-1)(2). b=1. See! In both cases we got the same value for b. And this completes our problem. The equation of the line that passes through the points (-3,4) and (2,-1) is y=-1x+1
yep
thx i have another :)
ok
i need to leave so what do you guyd think the answer is?
guys*
I honestly don't know.... O_O This is some wonky stuff......
trwakins1 what do you think?
umm im having trouble of course on the last one @carlyleukhardt @phi
GTG!!!!
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