Question

help!

Answer 1

@ribhu

Answer 2

@Michele_Laino

Answer 3

here we have to compute the distances FI and AD. Now we have this:
\[\begin{gathered}
dist\left( {FI} \right) = \sqrt {{{\left( { - 7 + 6} \right)}^2} + {{\left( { - 4 + 1} \right)}^2}} = \sqrt {1 + 9} = \sqrt {10} \hfill \\
dist\left( {AD} \right) = \sqrt {{{\left( {3 - 1} \right)}^2} + {{\left( {8 - 2} \right)}^2}} = \sqrt {4 + 36} = \sqrt {40} = 2\sqrt {10} \hfill \\
\end{gathered} \]
As we can see the distance AD is double of the distance FI, so we have to request that the distance AB is double of the distance FG.
Now the distance FG is:
\[dist\left( {FG} \right) = \sqrt {{{\left( { - 1 + 6} \right)}^2} + {{\left( { - 1 + 1} \right)}^2}} = \sqrt {25 + 0} = \sqrt {25} = 5\]
so the distance AB has to be \(2 \cdot 5=10\)
what is the point B such that the distance AB is equal to 10?
Hint: such point has to have the same y-coordinate of the point A

Answer 4

b? @Michele_Laino

Answer 5

correct!