Consider the two functions f(x)=x^2 -8x+7 https://northbranchsd.owschools.com/media/o_advalg_2015/2/img_g_alg02u09c03l20d_01.gif Do the minima of the two functions have the same x-value? Yes or No Which of the functions has the greater minimum? f(x) or g(x)
@amistre64 @Ghostgate @jim_thompson5910
Is it ok if i watch this because I don't really get functions and I still gotta learn them <plus i have the same question>
@YoloShroom
@Michele_Laino @mathstudent55
Idk I did this question and I got it wrong so I dont know what I got wrong.
f(x)=x^2 -8x+7 =x^2-8x+16-9=(x-4)^2-9\[\ge -9\]
*BRAIN CRAMPS* Ok lemme try translating that to english in my head................ yeahno it's not working.... please explain omo
now the minimum value is -9 and it is obtained when x=4 Also from the graph we can easily see that the curve has minima at x=4. so yes, both have the same x value at minima
@Austin1617
Oh. So does the f(x) or g(x) have a greater minimum?
min g(x)=-4 and min f(x)=-9 so????
Oh wow -_-
@jango_IN_DTOWN is a good teacher o:
*is still so confused* ;-; i hate being new to a topic
@FrostFlare23 may I help you? Which part you cant follow?
@jango_IN_DTOWN Well seeming I don't even get half of what you said I'd say I can't follow alot of it omo
Ok.. see f(x)=x^2 -8x+7= x^2-8x+16-16+7=(x-4)^2-9 Do you have any problem in this line? see I just put it in the form x^2+a
Weeell I understand what it says but I have a question of my own so you can explain functions there? I've literally had no experience with functions that is why I'm confused.
ok go for it
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