Question

Write the equation of a circle with a center at (1, 2) and a diameter of 15.

Answer 1

\[C:(x-1)^{2}+(y-2)^2=( \dfrac{15}{2})^{2}\]

Answer 2

Bacause the general formla is \[(x-q)^2 + (y-p)^2 = r^2\], where C(q,p) and radio is r, ok?

Answer 3

Sorry, replace "radio" to "radius"....

Answer 4

diameter=15 so radius is 15/2
equation of the circle radius r and centre (a,b) is given by (x-a)^2+(y-b)^2=r^2
So we have here cente (1,2) and radius 15/2
so the equation is (x-1)^2+(y-2)^2=(15/2)^2