Fill in the missing number to complete the factorization: x^3+14x^2+59x+70=(x+2)(x+5)(x+__________)
@amistre64 @ganeshie8 @Directrix
@zepdrix
Hint : constant term
\[\large\rm x^3+14x^2+59x+\color{orangered}{70}=(x+\color{orangered}{2})(x+\color{orangered}{5})(x+\color{orangered}{?})\]
Guessing the rational root theorem?
I don't get what you mean by constant term
The Remainder Theorem
with Factorization
constant term is the one without any x's attached to it
10?
\[\large\rm x^3+14x^2+59x+\color{orangered}{70}=(x+\color{orangered}{2})(x+\color{orangered}{5})(x+\color{orangered}{?})\] look at left hand side, whats the constant term ?
7?
do you mean 70 ?
yea
so 70 would be the constant term for the (x+____)
since above is an equation, left side and right side must have the same constant term
\[\large\rm x^3+14x^2+59x+\color{orangered}{70}=(x+\color{orangered}{2})(x+\color{orangered}{5})(x+\color{orangered}{?})\] look at right hand side, what could be the constant term ?
okay
you get the constant term on right hand side by multiplying these : \(\color{red}{2,5,?}\)
\[\color{Red}{70 = 2*5*?} \implies \color{red}{\dfrac{70}{10} = ?}\]
I DID SAID 7
you're correct
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