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Algebra 16 Online
OpenStudy (anonymous):

I have been at this for an hour please help

OpenStudy (anonymous):

Jason can paint a room in 6 hours. Lorissa can paint a room in only 3 hours. Which of the following can be used to determine the amount of time it would take for Jason and Lorissa to paint a room together? 1 over 6 plus 1 over 3 equals 1 over x 1 over 6 plus 1 over x equals 1 over 3 1 over x plus 1 over 3 equals 1 over 6 1 over 3 plus 1 over 6 equals x over 9

OpenStudy (anonymous):

@mathstudent55 @Nnesha @HS_CA @OregonDuck

OpenStudy (anonymous):

Please help me i am clueless

oregonduck (oregonduck):

i think it is A

OpenStudy (anonymous):

How?

oregonduck (oregonduck):

cause it is has to be x because together it would take 5 hours

oregonduck (oregonduck):

that is just what i am thinking

OpenStudy (mathstudent55):

Jason paints the room in 6 hours. He does 1/6 of the job in 1 hour. Lorissa can paint the room in 3 hours. She does 1/3 of the job in 1 hour. Together they take x hours to do the job. In 1 hour, they do 1/x of the job. In 1 hour they work: 1/6 + 1/3 = 1/x

OpenStudy (mathstudent55):

Working together it takes them 2 hours.

OpenStudy (anonymous):

thank you so much @mathstudent55

OpenStudy (mathstudent55):

You're welcome. BTW, @OregonDuck, you are correct that the answer is A, but it cannot take 5 hours working together. If Lorissa does the job in 3 hours, working together with Jason must make it faster than 3 hours, like 2 hours, not slower, like 5 hours.

oregonduck (oregonduck):

oh..ok now i get it

OpenStudy (mathstudent55):

Great.

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