Question

Jasmine drew a rectangle with the following properties.
• The area is 8 square centimeters.
• The length is twice the width.
What is the perimeter of Jasmine's rectangle?

Answer 1

let L = length
and W = width

LW = 8
L = 2W

know where to go from here?

Answer 2

8X2?

Answer 3

where is X coming from?

Answer 4

not sure?...

Answer 5

16?

Answer 6

we have two equations

LW = 8
L = 2W

we can do a substitution for L in the first equation get

2W^2 = 8

solve for W

Answer 7

2

Answer 8

2(2)^2=8

Answer 9

good, now find L

Answer 10

Let w be the width.
Area is w times length or w times 2w.
Solve w(2w) = 8 for w.

The perimeter is 2 times the half perimeter or 2(w+2w).

Answer 11

48?

Answer 12

is that right?

Answer 13

or 128?

Answer 14

you found W, which is 2

L = 2W = ?

Answer 15

8

Answer 16

What was your solution for w in the equation w(2w) = 8 or rewritten, 2 w^2 = 8 ?

Answer 17

nope

Answer 18

you width is 2
the length is twice the width, so the length is...?

Answer 19

they gave no equation

Answer 20

4 is length

Answer 21

good, now you have length and width

now find the perimeter.

Answer 22

width * length = 8 from the problem text.

Answer 23

16 is perimeter

Answer 24

not quite

Answer 25

perimeter = 2(length+width) = ?

Answer 26

perimeter is 8

Answer 27

again, not quite

Answer 28

The perimeter is 12. Can you work backwards to find the length.

Answer 29

length + width = ?

Answer 30

no
this is hard for me

Answer 31

12

Answer 32

12 is perimeter

Answer 33

length * width = area
2( length + width ) = perimeter

Answer 34

@caitlynmiller
12 is correct.

Answer 35

thank you