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Find the distance between the points (2, 3) and (0, 6).
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so do you know the distance formula?
looks like this :-) \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
if not, we can derive it.
\[\sqrt{?} (x2-x1)^{2}+(y2-y1)^{2}\]
yep yep, so now all you need to do is pick your \((x_1,y_1)\) and the sub twos and plug them in
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go ahead, give it a try
2.45 units?
leave it exact for me? That seems a little small
remember to square the result of your subtractions
still lost.
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Answer would be the square root of 13 Label your points. (2,3) (0,6) 2 is X1 0 is X2 3 is Y1 6 is Y2 Plug them in and you'll get the equation d=√(0-2)^2 + (6-3)^2 Simplify d=√(-2)^2 + (3)^2 Square d=√4+9 d=√13
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