Question

Answer choices are A,B,C,D.

Answer 1

@IrishBoy123 @Luigi0210 @HelpBlahBlahBlah @billchu

Answer 2

The speed will be the same around point C, since it's on the same height as the tossing point. Since there is a conservation of energy, the gravitational potential energy at any point is \[E _{gravitational} = mgh\]
where h is the height of the ball.
At both points h is the same and so the gravitational potential energy is the same.
The total energy equals
\[E _{total} = E _{gravitational} + E _{kinetic}\]

and so when the gravitational potential energy is the same. the kinetic energy is ought to be the same as well. The equation for the kinetic energy is
\[E = \frac{ 1 }{ 2 }mv ^{2}\]
and we know the mass of the ball remains constant. So, if the kinetic energy is the same, the speed is the same as well.