Question

In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)?
4NH3 + 6NO d 5N2 + 6H2O

The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

A.23.7 grams
B. 10.5 grams
C. 73.5 grams
D. 32.7 grams

Answer 1

NO= 14+16= 30 g/mol
NH3 = 14+3=17 g/mol

n= m/MM= 27.8 g/30 g/mol= 0.9266 moles of NO

0.9266 moles of NO x (4 mol NH3/6 mol NO) x (17 g NH3/mol/1mol NH3)= ????? g NH3