In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)?
4NH3 + 6NO d 5N2 + 6H2O

The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

A.23.7 grams
B. 10.5 grams
C. 73.5 grams
D. 32.7 grams

Question

In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)?
 4NH3 + 6NO d 5N2 + 6H2O

The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

A.23.7 grams
B. 10.5 grams
C. 73.5 grams 
D. 32.7 grams

cuanchi · Answer

NO= 14+16= 30 g/mol
NH3 = 14+3=17 g/mol

n= m/MM= 27.8 g/30 g/mol= 0.9266 moles of NO

0.9266 moles of NO x (4 mol NH3/6 mol NO) x (17 g NH3/mol/1mol NH3)= ????? g NH3