Question

Perform the operation and simplify the result if possible.
(2 m ^2 - 9) / (m^4 - 25) + (4 - m^2) / (m^4 - 25)

Answer 1

add the fractions (you have the same denominator)

then once you have added factor numerator and denominator to see if their are any common factors

Answer 2

I got m^2 -5/m^4 -25

Answer 3

\[\frac{m^2-5}{m^4-25}\]
great
factor the denominator you should see a common factor in the top and bottom after doing this

Answer 4

think difference of squares

Answer 5

okay thank you

Answer 6

\[\frac{ 2m ^{2} }{ (m ^{2}+5)(m ^{2}-5) }-\frac{ 9 }{ (m ^{2}+5)(m ^{2}-5) }+\frac{ 4 }{ (m ^{2}+5)(m ^{2}-5) }-\frac{ m ^{2} }{ (m ^{2}+5)(m ^{2}-5) }\]

This is how it starts out

Answer 7

ok so @Austin1617 as shown you how to factor the denominator
you should get
\[\frac{m^2-5}{(m^2-5)(m^2+5)} \]
you should see something that cancels @ludvic
and what mean by cancel here is that something divided by the same something is 0
provided that something isn't 0 itself
for example we know 4/4=1
-3/-3=1
and so on...
a/a=1 for all a excluding a=0

so this is what we mean by canceling here
\[\frac{m^2-5}{(m^2-5)(m^2+5)}=\frac{m^2-5}{m^2-5} \cdot \frac{1}{m^2+5}=...\]

Answer 8

it's m^2 +5 as the answer ?
@freckles

Answer 9

well why did you put m^2+5 on top?
it is on the bottom just a second ago?

Answer 10

so you put 1 over m^2 +5?

Answer 11

yep because that is what is left behind after replacing (m^2-5)/(m^2-5) with 1

Answer 12

and I think you mean 1 over (m^2+5)