The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width? 2w+2 times (5w)_96 2w+2 times (5w)96

Question

The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width? 2w+2 times (5w)<_96 2w+2 times (5w)>_96 2w+2 times (5w)<96 2w+2 times (5w)>96

anonymous · Answer

when you say _96 are you saying it's negative 96?

anonymous · Answer

no I was trying to make it the Greater than less than symbol sitting on the the line
but it is impossible

anonymous · Answer

oh ok, so let's approach this problem by first crossing out the choices we know for sure to be false.

How do you calculate the perimeters of a rectangle?

anonymous · Answer

LxW?

anonymous · Answer

that would be the formula for finding area

anonymous · Answer

oh

anonymous · Answer

|dw:1445666230314:dw|

perimeter is when you calculate the total lengths of the lines that make up the rectangle
Based on the picture I drew, what do you think the formula for calculating perimeters is?

anonymous · Answer

are you asking me for the answer or for what  the drawing is showing?

anonymous · Answer

I'm asking you what the formula for finding perimeters is...the drawing is simply supposed to provide visual help in case you're unsure

anonymous · Answer

ph, well I suck at math. sorry...

anonymous · Answer

oh*

anonymous · Answer

If I say that the perimeter can be found by adding up all the sides of the rectangle, will that help (because this is really simple math)

anonymous · Answer

yes that does help

anonymous · Answer

So then can you write the formula for how to calculate the perimeter of a rectangle?

anonymous · Answer

wouldn't it be 2w + 96L

anonymous · Answer

and where would the 96 come from?

anonymous · Answer

you're right about the 2w

anonymous · Answer

adding up both sides of the length?

anonymous · Answer

Since you don't have an actual given number for any of the rectangle's sides, you can't just plug in 96.  Another reason you can't plug in 96 is because that is the given perimeter of the triangle (and the sums of the rectangle's sides = 96)

Let's just forget about the actual problem for a bit and think about the generic formula for finding perimeters of rectangles
|dw:1445667042729:dw|
w = width of the rectangle
L = length of the rectangle

The perimeter of a rectangle is the sum of all the sides of the rectangle
Does that formula make sense?