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Algebra 7 Online
OpenStudy (anonymous):

Identify the focus, directrix, and axis of symmetry of x2=108y.

OpenStudy (anonymous):

2x or x^2? @uffa678

OpenStudy (tkhunny):

Find the Vertex. This will lead you on your way.

OpenStudy (tkhunny):

\(x^{2} = 108y\)

OpenStudy (anonymous):

well people do like to copy and paste alot.

OpenStudy (anonymous):

its X^2

OpenStudy (tkhunny):

That's better. Try to remember that "inline" typing just doesn't quite carry the same meaning as what appears in your textbook. Now, find that Vertex.

OpenStudy (anonymous):

so is the vertex (0,0)

OpenStudy (tkhunny):

Very good. Axis of symmetry is next. Go!

OpenStudy (anonymous):

wait how do i find that?

OpenStudy (tkhunny):

You look at it. Vertex Form is this, in your case. \(108(y - 0) = (x-0)^{2}\). Those 0s helped you find the Vertex. The Axis of Symmetry is also in there. Since the Vertex is (0,0), the Axis of Symmetry must be either x = 0 or y = 0. Which is it. It ALWAYS goes through the Vertex.

OpenStudy (anonymous):

so the acid of symmetry is always the vertex or no?

OpenStudy (anonymous):

axis*

OpenStudy (tkhunny):

No, the Vertex is a point. The Axis of Symmetry is a line that contains that point. If you fold your parabola on the Axis of Symmetry, you will see that you have exact copies on each side.

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