How would you go about doing this question without a calculator. I know I have to know my unit circle for this. but yea how would one go about solving this problem without a calculator?
So for the first question I got into polar form using oilers formula \[e ^{\frac{ 4\pi i }{ 3 }}\] Its kind of hard to see that but its says e^(4pi(i)/3)
\[(e ^{\frac{ 4\pi \iota }{ 3}})^{111}\]
how would I get the exact value for this in the form a + bi
@freckles
put it into trig form
at least thats my first thought
bah, im not real sure what the question is asking for i spose ...
its asking to raise it to the power of 111 and simply if it to put into a + bi form
(r,t)^n = (r^n, nt) right?
r,t being the ordered pair for (r,t) -> r(cos(t) + i sin(t))
yes
it appears r = 1, since its the unit circle, what is t?
4pi/3 I believe
something about 60 yes, and the other is something about 45
111 (4pi/3) ... reduces to what in periodic terms?
148pi?
can we simplify that to between 0 and 2pi?
thats where im getting stuck, how would you do that?
2k = 148, when k=74 so 74 revolutions gets us to 148 right?
yes
then 148 pi is just a large version of 2pi
which is just a slightly larger version of 0
cos(0) + i sin(0)
1+0i
444pi/3 = 148pi = k*2pi
yes
what I dont understand is that how did you know 148pi is equivalent to 2pi?
becuase a circle repeats itself every 2pi ... so 2pi = 4pi = 6pi = ... how many times does 2pi go into 148pi? how many times does the circle turn around on itself?
74 times
then 74 revolutions just gets us back to the start of the circle |dw:1445712174118:dw|
ok so say the angle was 195pi how would you get the equivalent angle between 0 and 2pi?
divide it by 2pi, whats the remainder?
1/2
then 1/2 of 2pi is pi
if its not a full rotation of 2pi, then its a partial rotation ...
after 97 rotation, we have 1/2 a rotation
so an angle of 873 pi would also be equivalent to pi?
cuz 873/2= 436.5. and remainder is 0.5
spose we have 23.3247 rotations of 2pi ... then we have 23 + 0.3247 rotations ...
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