Question

Will medal attaching picture

Answer 1

6,7,&8

Answer 2

& 9

Answer 3

first part of your exercise can be modeled by this equation:
\(L=30+W\)
where \(L\) is the length, and \(W\) is the width of the soccer field

Answer 4

furthermore, from your data, we can write this condition:
\(L \cdot W=8800\)

Answer 5

Substituting the first equation, into the second one, we get:
\[\left( {30 + W} \right) \cdot W = 8800\]
which is a quadratic equation. Please solve such equation

Answer 6

I'm confused @Michele_Laino

Answer 7

If I apply the distributive property of multiplication over addition, we get:
\[30W + {W^2} = 8800\]
therefore I simplify, so I get:
\[{W^2} + 30W - 8800 = 0\]
please solve that equation for \(W\)

Answer 8

how do i that? I don't know what W is and there arent any like terms?

Answer 9

please, do you know how to solve a quadratic equation?

Answer 10

not really..

Answer 11

i can look it up?

Answer 12

w(w+30)=8800

Answer 13

I'm sorry, it is not the right procedure for solving a quadratic equation

Answer 14

so how do i this problem??

Answer 15

I'm thinking...

Answer 16

sincerely speaking, I don't know how we can solve your problem without solving a quadratic equation

Answer 17

please try to ask to another helper

Answer 18

@dan815 please help

Answer 19

@ freckles please help

Answer 20

@freckles

Answer 21

i really need help :( thank you @Michele_Laino for trying!

Answer 22

:)

Answer 23

i got 7 and 8

Answer 24

i really need 6

Answer 25

I'm sorry, the solution is \(W=80\), so \(L=80+30=110\)

Answer 26

i got 6!

Answer 27

now 9 i have to find 9 lol

Answer 28

please, what is \(6\)?

Answer 29

one second

Answer 30

http://openstudy.com/study#/updates/52d86379e4b02397b18db85b

Answer 31

The quadratic formula for this solution:
\[w=\frac{-b \pm \sqrt{b^2-4ac} }{ 2a }\]


Subsitute the values a=1, b=30, and c=-8800 into the quadratic formula to solve x.

\[w=\frac{ -30\pm \sqrt{(30)^2 -4(1)(-8800)} }{ 2(1) }\]

Simplify the section inside the radical.

\[w=\frac{ -30 \pm \sqrt{30^2-4 * 1 * -8800} }{ 2(1) }\]

Raise 30 to the power of 2 to get 900.

\[w=\frac{ -30 \pm \sqrt{900-4 * -8800} }{ 2 }\]

Multiply -4 by -8800 to get 35200.

\[w=\frac{ -30+\sqrt{900+35200} }{ 2 }\]

Add 900 and 35200 to get 36100.

\[w=\frac{ -30\pm \sqrt{36100} }{ 2 }\]

Rewrite 36100 as 190^2.

\[w=\frac{ -30\pm \sqrt{190^2} }{ 2 }\]

Get rid of the terms from the radical.
\[w=\frac{ -30\pm190 }{ 2 }\]

Simplify it

\[\frac{( -30+190) }{ (2) }\]

\[w=-15\pm95\]

w= -15+95= 80

w=-15-95=110

w=80,-110

Answer 32

@angelmaxine @Michele_Laino

Answer 33

whoa :o thank you!

Answer 34

@Austin1617

Answer 35

for #9 can i post what i got ? and can you look over it @Austin1617

Answer 36

Let x = the width and x + 30 = the length.

x(x + 3) = 8800
x^2 + 3x = 8800
x^2 + 3x - 8800 = 0
Using the Quadratic Formula, I get x ≈ 92.320 yd and x + 30 ≈ 122.320 yd.

2x + 2x + 60 = 600
4x + 60 = 600
4x = 540
x = 135
x + 30 = 165

The area would be 22275 yd^2.

Answer 37

@Austin1617 @Michele_Laino

Answer 38

please, the right equation is:
x(x+30)=8800

Answer 39

@Michele_Laino sorry typo

Answer 40

does everything else look ok