If sin Θ = 5 over 6, what are the values of cos Θ and tan Θ?
what have you tried?
wym
there are several methods to solve this, triangle method, trigonometric identities, etc... which one are you comfortable with?
triangle
\(\sin^2 x + \cos^2 x =1\) you have sin value, plug that in and find the cos value!
where did u get those number from
thats a trigonometric identity that you can use. sin x = 5/6 is given so \((5/6)^2 + \cos^2 x =1\) only cos x is unknown here, isolate it and find its value :)
cos will be 11
how did u get that? can you show me your workings?
i added 6+5
let me show you the workings and you let me know if you have any doubts in that, \((5/6)^2 +\cos^2 x =1 \\ \cos^2 x = 1 -(5/6)^2 \\ \cos^2 x = 1- 25/36 \\ \cos^2 x = (36-25)/36 \\ \cos^2 x = 11/36 \\ \cos x = \sqrt{11/36} \\ \cos x = \dfrac{\sqrt {11}}{6} \\ \) thats your answer for cos. tan is very easy, just tan x = sin x/ cos x try to get it :)
thank u
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