**Will give medals** super easy question https://gyazo.com/88304e36ca292c2ba33e60295af966d4
You're given that (5, 3, 5) is a point on the plane. Let (x, y, z) be any other point on the plane, then the vector joining these two points is (x-5, y-3, z-5)
since the vector (-5, 2, -3) is perpendicular to the plane, it is perpendicular to any vector in the plane also
what do you know about the relationship between dot product and perpendicular vectors ?
i could use the dot product to calculate this?
Yes, dot product is 0 if vectors are pendicular : (x-5, y-3, z-5) . (-5, 2, -3) = 0
simplify
x=5 , y=3, z=5?
sorry im confused, can you do this problem with me?
we're looking for an equation of a plane, not solving variables.. (x-5, y-3, z-5) . (-5, 2, -3) = 0 -5(x-5) + 2(y-3) -3(z-5) = 0
-5x+2y-3z=-10?
34 sorry
do you mean -5x+2y-3z = -34
perfect thank you:D if i post another one will you help? ahah
yes
il try..
Join our real-time social learning platform and learn together with your friends!