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Mathematics 14 Online
OpenStudy (anonymous):

**Will give medals** super easy question https://gyazo.com/88304e36ca292c2ba33e60295af966d4

ganeshie8 (ganeshie8):

You're given that (5, 3, 5) is a point on the plane. Let (x, y, z) be any other point on the plane, then the vector joining these two points is (x-5, y-3, z-5)

ganeshie8 (ganeshie8):

since the vector (-5, 2, -3) is perpendicular to the plane, it is perpendicular to any vector in the plane also

ganeshie8 (ganeshie8):

what do you know about the relationship between dot product and perpendicular vectors ?

OpenStudy (anonymous):

i could use the dot product to calculate this?

ganeshie8 (ganeshie8):

Yes, dot product is 0 if vectors are pendicular : (x-5, y-3, z-5) . (-5, 2, -3) = 0

ganeshie8 (ganeshie8):

simplify

OpenStudy (anonymous):

x=5 , y=3, z=5?

OpenStudy (anonymous):

sorry im confused, can you do this problem with me?

ganeshie8 (ganeshie8):

we're looking for an equation of a plane, not solving variables.. (x-5, y-3, z-5) . (-5, 2, -3) = 0 -5(x-5) + 2(y-3) -3(z-5) = 0

OpenStudy (anonymous):

-5x+2y-3z=-10?

OpenStudy (anonymous):

34 sorry

ganeshie8 (ganeshie8):

do you mean -5x+2y-3z = -34

OpenStudy (anonymous):

perfect thank you:D if i post another one will you help? ahah

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

il try..

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