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Mathematics 11 Online
OpenStudy (anonymous):

http://prntscr.com/8v2fhv http://prntscr.com/8v2gio

OpenStudy (owlcoffee):

Let's begin with the first one, but first, some theory... Difference of squares is a factorization identity which allows me to calculate the roots of any polynomial with the form: \(A^n - b^n\) With ruffinis method we obtain: \((a-b)(a^{n-1}+a ^{n-2}b+...b ^{n-2}a+b ^{n-1})\). And this last equality actually shows the pattern any exponential difference has as a factorial form, which comes in handy when conjugating square roots and so on. So, on the problem in the forst image, on the above position, we take the expression: \[4x^2-81=0\] And recognize the squares, of course, \(81=9^2\) and \(4=2^2\) these are exponents you should already know about, so we will just replace them: \[2^2x^2-9^2=0\] But, let's associate that \(2^2x^2\) to \((2x)^2\) since "2" and "x" are multiplying each other and it respects a property of exponents. : \[(2x)^2-9^2=0\] And as you can see, we now can apply the difference of squares which replacing "n" for "2" on the pattern I showed to you, we get : \(a^2-b^2=(a-b)(a+b)\) and that is the formula for this factorization, where "a", in this case is represented by "2x" and "b" is represented by "9": \[(2x-9)(2x+9)=0\] And now, this is ready to be solved for "x", which I'll leave to you.

OpenStudy (anonymous):

so the answer would be C

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

#1 left off here: (2x + 9)*(2x - 9) = 0 Zero Product Property 2x + 9 = 0 or 2x - 9 = 0 2x = -9 or 2x = 9 x = ? or x = ?

OpenStudy (anonymous):

so the answer is A?

Directrix (directrix):

No. You have to divide each of these by 2 to solve for x. 2x = -9 or 2x = 9

Directrix (directrix):

You already answered this question earlier in the thread.

OpenStudy (anonymous):

I got C

Directrix (directrix):

If that is #15, option C is correct if it is -9/2 and 9/2

Directrix (directrix):

For #16, click here and scroll down to see the results. http://www.wolframalpha.com/input/?i=2x%5E2+-+11x+-+6+%3D+0

OpenStudy (anonymous):

ok i got the answer and for the last one?

OpenStudy (anonymous):

i got B

Directrix (directrix):

What number is the last one and what about #17?

Directrix (directrix):

B is correct for the x^2 + 5x = -1 problem.

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