Question

I need assistance kinetics lab

Answer 1

i have all my data i just need assistance

Answer 2

Wow no one is going to help me

Answer 3

What kind of help do you need? can you post your questions?

Answer 4

its a kinetics

Answer 5

I can take a pic over of the data and table did the calacultion but i cant find how to find the order of the reaction

Answer 6

Anyone there

Answer 7

show me the data I will try to help you

Answer 8

Thank you

Answer 9

one sec im uploading it

Answer 10

do you have the reaction?

Answer 11

Yes i do
ill type it

Answer 12

6I- + Bro3- + 6H+ ____> 3I2 +Br- +3H2O

Answer 13

are you sure the rate is well calculated?

Answer 14

rate= K(I-)^m(BrO3-)^n(H+)^P

Answer 15

what do you mean

Answer 16

here were some instructions and table info i used to calculate

Answer 17

This is what the instructions said i was suppose to to then and here is my working to porve

Answer 18

because when you decrease the concentration of I- and H+ looks like the rate of the reaction is higher meaning that when you decrease one of the reactants the reaction go faster

Answer 19

understood

Answer 20

Usually when you increase the reactant the rate increase or remain the same, if they decrease the order will be negative. It can happens in certain reactions but I don't think will be this case.

Answer 21

the first table i sent written pen is my data and calculation of the concentration of the reactants.
The second data table i sent was used for my caluclation to determine my M2 and plus was the amounts used in actually experiment from intially 100ml of concentration.

Answer 22

I have learnt how to find order of reactant in lecture. I understand in lab some numbers are not clean cut but i honestly do not know what to do cause im getting nasty number. The possible order i can get are from the options 1, 2, and or 0 from the instructions i sent on how to find order of reactnts.

Answer 23

Yea I see...
Please review the concentrations calculations because from table 19-1 looks to me that the concentration of I- in the second experiment is double than in the first one and BrO3- is double in the 3rd experiment than in the first and second and protons is also double in the 4th experiment respect to the 1,2,3.

Answer 24

I did i sent you a pic.

Answer 25

Here is how i found the concentration of reaction mixture 1 from the data from table 19-1

Answer 26

Your final volume when you mix tube 1 and 2 will be for all the experiment 50mL

Answer 27

What?

Answer 28

why?

Answer 29

oh wait dont answer that question. I see

Answer 30

that would not work though this is how my table is coming out

reaction1 I- is 0.02M BrO3- is 0.08 H+ is 0.2
2 is 0.02M is0.08 is 0.2
basically the are all coimng out the same

Answer 31

KI KBrO3 HCl
1 0.002 0.008 0.02
2 0.004 0.008 0.02
3 0.002 0.016 0.02
4 0.002 0.008 0.04

Answer 32

so use the intial from 19-1 and the final as 50ml right?

Answer 33

yea

Answer 34

oh cause i was using 100ml from the instructions as a the intial

Answer 35

do you got it now?

Answer 36

yes but do i use the book method to solve for rate order as
rate1/rate2
or is use as i was taught in lecture rate 2/rate1

Answer 37

because i never really solved order based on ratios. they were simply strightforward if not i would have to take the ln

Answer 38

doesn't matter if you use rate 2/1 or rate 1/2 you will get the same answer because you have to do in parallel the rate of concentrations in the same order.
I usually choose the bigger divided by the smaller so I get a number bigger than 1

Answer 39

that what i would do too.

Answer 40

when i found the rate order for I- i ill call x the power
i got
0.429=0.5^x
there x would be 1
or first order

Answer 41

Now you can see from 1 and 2 if you duplicate the concentration of I- the rate increase also double, what is going to be a 1st order for I-
If you duplicate the concentration of

Answer 42

0.004