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Suppose that f’’ is continuous everywhere. ( 4 points each) a. If f’(-3) = 0 and f’’(-3) = 5, what can you say about f(x)? b. If f’(5) = 0 and f’’(5) = -7, what can you say about f(x)?
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\(\large\color{black}{ \displaystyle f'(-3)=0 }\) \(\large\color{black}{ \displaystyle f''(-3)=5 }\) this is what you have for part A?
You can say that the function is concave up at x=-3 (because the slopes are increasing which is given by the second derivative).
Also, you can tell there is a local minimum at x=-3.
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