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Heres the queston: If 6.00 g of Cacl2 X 2H2O AND 5.5 g of NaCO3 are allowed to react in aqueous solution, what mass of CaCO3 is produced? Answer the question by typing the answer in the spaces. (6.00 g CaCl2 ∙ 2 H2O / 1)*(1 mol CaCl2 ∙ 2 H2O / ____ g CaCl2 ∙ 2 H2O)*( ___ mol CaCO3 / ____ mol CaCl2 ∙ 2 H2O)*( ____g CaCO3 / 1 mol CaCO3) =___ g CaCO3 (5.50 g Na2CO3 / 1)*(1 mol Na2CO3 / ____g Na2CO3 )*( ___ mol CaCO3 / ____ mol Na2CO3)*( ___ g CaCO3 / 1 mol CaCO3) = ____ g CaCO3
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