Question

Also this problem please help ASAP
8^-1/2

Answer 1

0.35

Answer 2

\[8^{-1/2}=\frac{ 1 }{ 8^{1/2} }=\frac{ 1 }{ \sqrt{8} }=\frac{ 1 }{ 2\sqrt{2} }\]

Answer 3

But how?

Answer 4

i showed you @Angel_Kitty12

Answer 5

Oh. But isn't it not allowed to have a radical in the denominator?

Answer 6

easy: \[\frac{ 1 }{ \sqrt{8} }=\frac{ 1 }{ \sqrt{8} }*\frac{ \sqrt{8} }{ \sqrt{8} }=\frac{ \sqrt{8} }{ 8}\]

Answer 7

So would it be 2sqrt2/8 ?

Answer 8

\[\frac{ \sqrt8 }{ 8}=\frac{ 2\sqrt{2} }{ 8 }\]

Answer 9

so yeah you are correct

Answer 10

Then simplifies to sqrt2/4 ?

Answer 11

yeah

Answer 12

\[\frac{ \sqrt2 }{ 4 }\]

Answer 13

And that's the answer right?

Answer 14

yeah