Question

Math help please! Last 3! Will fan medal and testimonial!

Answer 1

Oh I haven't covered this so I'm not sure...So sorry! Maybe @celinegirl @nevermind_justschool @PizzaLover123 can help? Sorry!

Answer 2

These are my last 3 questions! Please help!

Answer 3

That's ok! @pinkcandyrosez882

Answer 4

@TheSmartOne @They_Call_Me_Narii @Jaynator495 @LazyBoy @Michele_Laino @imammalik_806

Answer 5

whats the question

Answer 6

I posted it in an attatchement
look above

Answer 7

i have to say....c but im not shure

Answer 8

@studydood66

Answer 9

explain please?

Answer 10

for the first one? I have 3 up.

Answer 11

It is D!

Answer 12

dont just say answers @xMissAlyCatx thats against the code of conduct!

Answer 13

the equation for volume of a cylinder is V=pi (r^2) (h)
The equation for a cone is similar V= pi (r^2) (h/3)

Answer 14

hint:
volume \(V\) of a cone with radius \(r\) and height \(h\), is:
\[\huge V = \frac{1}{3}\pi {r^2}h\]

Answer 15

I'm sorry I have no idea how to do this @Michele_Laino

Answer 16

we have radius \(r=3\) and height \(h=7\) so we can write this:
\[\Large V = \frac{1}{3}\pi \cdot \left( {{3^2}} \right) \cdot 7 \cong \frac{1}{3} \cdot 3.14 \cdot \left( {{3^2}} \right) \cdot 7\]

Answer 17

THANK YOU! Can you please help me with the other 2?

Answer 18

ok!

Answer 19

question #2
here we can write this proportion:
\[\Large \pi {R^2}:360 = A:37\]
where \(A\) is the requested area, and \(R\) is the radius of the pie, and, as usually, \(\pi=3.14159...\)

Answer 20

so, if we apply the fundamantal property of proportions, we can write this:
\[\Large A = \frac{{\pi {R^2} \cdot 37}}{{360}} \cong \frac{{3.14 \cdot {{\left( {17.5} \right)}^2} \cdot 37}}{{360}} = ...?\]
since \(R=d/2=35/2=17.5\)

Answer 21

please complete my computation above

Answer 22

fundamental*

Answer 23

98.83! Correct?

Answer 24

yes, correct!

Answer 25

Yay! Last one!

Answer 26

question #3
here the requested volume is half of the volume of a sphere, so we can write:
\[\Large \begin{gathered}
V = \frac{1}{2} \cdot \frac{{4\pi }}{3}{R^3} \cong \frac{1}{2} \cdot \frac{4}{3} \cdot \frac{{22}}{7}{R^3} = \hfill \\
\hfill \\
= \frac{1}{2} \cdot \frac{4}{3} \cdot \frac{{22}}{7}{12^3} = ...? \hfill \\
\end{gathered} \]
where \(R\) is the radius of the sphere, so we have: \(R=D/2=24/2=12\)

Answer 27

what do you get?

Answer 28

confused.... I got... really confused.

Answer 29

@Michele_Laino

Answer 30

WAIT YES! I GOT IT THANK YOU!