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OpenStudy (xmissalycatx):
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OpenStudy (love_to_love_you):
The bacterium, cholera, reproduces at an exponential rate which can be modeled through the continuous growth model. If the value for k is 1.38 and we initially start with 2 bacteria, what is the equation for cholera growth, where t is the number of hours?
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OpenStudy (anonymous):
do u have answer choices
OpenStudy (love_to_love_you):
I figured it out :) but here are my answer choices
OpenStudy (love_to_love_you):
a. A(t) = 2e^1.38×t
b. A(t) = 2e^1.38×2t
c. A(t) = –2e^1.38×t
d. A(t) = 2e^–1.38×t
OpenStudy (love_to_love_you):
I think it's A
OpenStudy (anonymous):
what makes you think it is a??
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OpenStudy (anonymous):
i just wanna know how you figured it out
OpenStudy (love_to_love_you):
It's not C or D
OpenStudy (love_to_love_you):
give me a sec so I can type it all
OpenStudy (love_to_love_you):
The problem can be modeled with an exponential growth function which makes it so at t=0 the function has to be equal to 2 so C and D can be ruled out because of the -
OpenStudy (love_to_love_you):
And from there on I figured it would be A because we started with 2 bacteria.
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