What are the roots of this function?
I know \[y = x^{3}+4x^{2}+3x=0\]
roots/solutions/zeros/x-intercepts: are points where line intersect the x-axis
The roots are simply the x-intercepts. Just get them from the graph
But is there another way to write the roots?
Find the zeros of the equation by looking at the degree...
Are you on zeros of polynomial equations yet? Or?
This cubic is easily factored. Then set each factor equal to zero to get the roots.
Yes just factor it
that's polynomial equation you will write roots as x= 1st root,,2nd root,3rd root
In what way? Do you mean simplify the roots?
where does it hit the x axis?
We've told you that the roots are the x-intercepts, the points where the graph meets the x-axis. Look at the graph and write down those three x-values.
no. in other words roots are x-intercept ( a point where line intersect x-axis)|dw:1445993808576:dw|
So the roots are (0,0) ; (-1, 0) ; (-3, 0) ?
looks good
Ok, thanks!!
you can check ur answer by substituting x for each root if you get 0 as final answer then 100% those numbers are the root
np
For some reason, I can't type that into the answer box...
those are ordered pair x = 1st root , 2nd root , 3rd root write like this
Technically, the roots are just the x-values where y=0, so you wouldn't write ordered pairs. The roots are \[x=\left\{ -3,-1,0 \right\}\]
Join our real-time social learning platform and learn together with your friends!