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Mathematics 22 Online
OpenStudy (anonymous):

Which relationship is always correct for the angles p, q, and r of triangle ABC? p + r = q p + q + r = 180 degrees p + q + r = 90 degrees q + r = p

OpenStudy (anonymous):

OpenStudy (anonymous):

@StudyGurl14

OpenStudy (anonymous):

i think its b

OpenStudy (anonymous):

@texaschic101 @misty1212

OpenStudy (studygurl14):

B is incorrect.

OpenStudy (anonymous):

can you explain why pls?

OpenStudy (anonymous):

@StudyGurl14 what about d?

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

if pqr are the 3 angles of a triangle, then yes .. they add up to 180 always (assuming euclidean geometry of course)

OpenStudy (anonymous):

wait... so b is correct?

OpenStudy (amistre64):

but then theres a picture .... so disregard that

OpenStudy (anonymous):

lol

OpenStudy (amistre64):

since p is not part of the triangle angles proper ... b is not correct consider that the angle related to p in the triangle is: 180-p, since it forms a straight line now; add up those angles (180-p)+q+r = 180

OpenStudy (anonymous):

but what is p? i dont have any numbers

OpenStudy (amistre64):

solve the relationship ....

OpenStudy (anonymous):

how would i do that? im kinda confused :/

OpenStudy (amistre64):

|dw:1446051852964:dw| does x+p = 180?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

|dw:1446051895839:dw| does q+r+x = 180?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

if 2 things are equal to another, then they are equal to each other x+p= 180 x+q+r = 180 x+p = x+q+r ..... what can we conclude?

OpenStudy (anonymous):

180 + 180 = 360

OpenStudy (amistre64):

no, we are solving for p

OpenStudy (anonymous):

p would be 90?

OpenStudy (amistre64):

does: x+n = x+n ?? if so, then x+(p) = x + (q+r) n n

OpenStudy (anonymous):

ohh

OpenStudy (amistre64):

since n=n ... p=n ... p=q+r

OpenStudy (anonymous):

wait a sec pls

OpenStudy (anonymous):

so then i was right on my second guess, the answer is d?

OpenStudy (amistre64):

if your guessing, then who knows ... but since we just proved it, yes :)

OpenStudy (anonymous):

lol i didnt mean it like that :) thx

OpenStudy (amistre64):

good luck :)

OpenStudy (anonymous):

i might have some more questions so could you help? if i do, of course lol ill summon you

OpenStudy (anonymous):

thx

OpenStudy (amistre64):

i might be attending to my own real life issues ... but if im available ill see what i can do

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