Which relationship is always correct for the angles p, q, and r of triangle ABC?
p + r = q
p + q + r = 180 degrees
p + q + r = 90 degrees
q + r = p
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OpenStudy (anonymous):
OpenStudy (anonymous):
@StudyGurl14
OpenStudy (anonymous):
i think its b
OpenStudy (anonymous):
@texaschic101 @misty1212
OpenStudy (studygurl14):
B is incorrect.
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OpenStudy (anonymous):
can you explain why pls?
OpenStudy (anonymous):
@StudyGurl14 what about d?
OpenStudy (anonymous):
@amistre64
OpenStudy (amistre64):
if pqr are the 3 angles of a triangle, then yes .. they add up to 180 always (assuming euclidean geometry of course)
OpenStudy (anonymous):
wait... so b is correct?
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OpenStudy (amistre64):
but then theres a picture .... so disregard that
OpenStudy (anonymous):
lol
OpenStudy (amistre64):
since p is not part of the triangle angles proper ... b is not correct
consider that the angle related to p in the triangle is: 180-p, since it forms a straight line
now; add up those angles
(180-p)+q+r = 180
OpenStudy (anonymous):
but what is p? i dont have any numbers
OpenStudy (amistre64):
solve the relationship ....
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OpenStudy (anonymous):
how would i do that? im kinda confused :/
OpenStudy (amistre64):
|dw:1446051852964:dw|
does x+p = 180?
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
|dw:1446051895839:dw|
does q+r+x = 180?
OpenStudy (anonymous):
yes
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OpenStudy (amistre64):
if 2 things are equal to another, then they are equal to each other
x+p= 180
x+q+r = 180
x+p = x+q+r
..... what can we conclude?
OpenStudy (anonymous):
180 + 180 = 360
OpenStudy (amistre64):
no, we are solving for p
OpenStudy (anonymous):
p would be 90?
OpenStudy (amistre64):
does:
x+n = x+n ??
if so, then
x+(p) = x + (q+r)
n n
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OpenStudy (anonymous):
ohh
OpenStudy (amistre64):
since n=n ... p=n ... p=q+r
OpenStudy (anonymous):
wait a sec pls
OpenStudy (anonymous):
so then i was right on my second guess, the answer is d?
OpenStudy (amistre64):
if your guessing, then who knows ... but since we just proved it, yes :)
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OpenStudy (anonymous):
lol i didnt mean it like that :) thx
OpenStudy (amistre64):
good luck :)
OpenStudy (anonymous):
i might have some more questions so could you help? if i do, of course lol ill summon you
OpenStudy (anonymous):
thx
OpenStudy (amistre64):
i might be attending to my own real life issues ... but if im available ill see what i can do