Question

help please :)

Answer 1

not exactly sure how to do this...

Answer 2

@Cuanchi

Answer 3

The water will flow to the side with more active particles
in your case A sol 0.3 M KCl will produce two particles per molecule then you will have a total of 0.6 M particles
B solution 0.2M Na3PO4 will dissociate and form 4 particles (3 form Na+ and one from PO4-3)then you will have 0.2 x 4= 0.8 M particles

you can figure out the rest?

Answer 4

so would C6H12O6 break up into 24 particles?

Answer 5

glucose doesn't dissociate, then the number of particles will be equal to the initial molarity.
K2SO4 will produce 3 particles or ions (2K+ and one SO4-2)
LiNO3 will produce 2 particles, (Li+ and NO3^-2)
NiBr2 will produce 3 particles ( Ni+2 and 2 Br-)

Answer 6

glucose is a covalent or molecular compound
The others are ionic compounds

Answer 7

ohh ok makes sense now :) thank you!

Answer 8

I assume that the membrane only let pass the water and not the ions. If the membrane let pass the ions then at the end the water will be in equilibrium no moving to any side

Answer 9

yeah there is no net flow for B and left for C